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Question:

Energy stored in between the plates of parallel plate capacitor of area A, separated by distance d is:

12ε0E2Ad

12Adε0E2

12ε0E2Ad

12ε0dE2A

Solution:

Energy stored in a capacitor of capacitance: E = 1/2CV²
Capacitance of parallel plate capacitor = ε₀A/d
Potential difference across parallel plate capacitor due to presence of electric field, V = E × d
Thus, energy stored in capacitor = 1/2(ε₀A/d)(Ed)² = 1/2ε₀E²Ad