2.85
5.7
22.8
11.4
Correct option is D. 22.8I₂(s) → I₂(g): ΔH₁ = 24 cal/g at 200°CΔH₂ = ΔH₁ + ΔCp(T₂ - T₁)= 24 + (0.031 - 0.055) × 50= 24 - 1.2= 22.8 cal/g