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Question:

Equation of travelling wave on a stretched string of linear density 5g/m is y=0.03sin(450t-9x) where distance and time are measured in SI units. The tension in the string is :

10N

12.5N

7.5N

5N

Solution:

The correct option is B
12.5N
y=0.03sin(450t-9x)
v=ω/k=450/9=50m/s
v=√(T/μ) ⇒Tμ=2500 ⇒T=2500×5×10⁻³=12.5N