∫dx/(x⁵+3)Let ∫x⁴dx/(x⁵+3)Assume, x⁵=tDifferentiate t with respect to x, 5x⁴dx=dt=1/5∫dt/(t+3)=1/5 ∫(1/t - 1/(t+3))dt=1/5[log t - log(t+3)] + c=1/5log(t/(t+3)) + c=1/5log(x⁵/(x⁵+3)) + c