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Question:

Evaluate the following using suitable identities: (i)(99)³ (ii)(102)³ (iii)(998)³

Solution:

(i)99³=(100-1)³=(100)³+(-1)³+3(100)(-1)(100-1)=1000000-1-300(100-1)=1000000-1-30000+300=970299
(ii)102³=(100+2)³=(100)³+(2)³+3(100)(2)(100+2)=1000000+8+600(100+2)=1000000+8+60000+1200=1061208
(iii)998³=(1000-2)³=(1000)³-(2)³+3(1000)(-2)(1000-2)=1000000000-8-6000(1000-2)=1000000000-8-6000000+12000=994011992