Excess of NaOH(aq) was added to 100 mL of FeCl3(aq) resulting in 2.14 g of Fe(OH)3. The molarity of FeCl3(aq) is: [Given molar mass of Fe = 56 g/mol and molar mass of Cl = 35.5 g/mol] 0.2M 0.6M 1.8M 0.3M<p></p>

3NaOH + FeCl3 → 3NaCl + Fe(OH)3
The ratio between FeCl3 and Fe(OH)3 is 1:1
Molar mass of Fe(OH)3 = 56 + 3(35.5) = 107 g/mol.
2.14 g of Fe(OH)3 = 2.14g / 107g/mol = 0.02 mol Fe(OH)3 = 0.02 mol FeCl3
Total volume = 100 mL = 0.100 L
The molarity of FeCl3(aq) = 0.02 mol / 0.100 L = 0.2 M
Hence, the correct option is D

Eduprobe

Question:

Excess of NaOH(aq) was added to 100 mL of FeCl3(aq) resulting in 2.14 g of Fe(OH)3. The molarity of FeCl3(aq) is: [Given molar mass of Fe = 56 g/mol and molar mass of Cl = 35.5 g/mol] 0.2M 0.6M 1.8M 0.3M

Solution: