devarshi-dt-logo

Question:

Express the trigonometric ratios sinA, secA, and tanA in terms of cotA.

Solution:

We know, cosec²A = 1 + cot²A
1/cosec²A = 1/(1 + cot²A)
sin²A = 1/(1 + cot²A)
sinA = ±1/√(1 + cot²A)
∴ sinA = 1/√(1 + cot²A)
We know, sec²A = 1 + tan²A
sec²A = 1 + 1/cot²A = (cot²A + 1)/cot²A
∴ secA = √[(cot²A + 1)/cot²A]
We know, tanA = 1/cotA