In given figure depicts a racing track whose left and right ends are semicircular. The distance between the two inner parallel line segments is 60m and they are each 106m long. If the track is 10m wide, find: (i) The distance around the track along its inner edge (ii) The area of the track

The distance around the track along its inner edge=EF+HG+circumference of semicircle with diameter EH+circumference of semicircle with diameter FG
circumference of semicircle with diameter EH+Circumference of semicircle with diameter FG=2×π×30=60πm∴The distance around the track along its inner edge=60π+106+106=28047m∴Area of track=Area of rectangle ABFE+Area of rectangle HGCD+(Area of semicircle with diameter AD−Area of semicircle with diameter EH)+(Area of semicircle with diameter BC−Area of semicircle with diameter FG)=(106×10)+(106×10)+((π/2×40×40)−(π/2×30×30))+((π/2×40×40)−(π/2×30×30))=2120+2200=4320m2