Figure shows a circuit that contains three identical resistors with resistance R=9.0 Ω each, two identical inductors with inductance L=2.0 mH each, and an ideal battery with emf ε=18 V. The current 'i' through the battery just after the switch closed is, ....4 mA 0.4 A 4 A 0 ampere
4 A
0ampere
4 mA
0.4 A
Solution:
At t=0, (switched on) capacitor behaves as short circuit. Inductor behaves as open circuit. Here Req=R/2 so, i=ε/Req=18/(9/2)=4A