50µF and 30µF
20µF and 30µF
60µF and 40µF
40µF and 10µF
The correct option is D 40µF and 10µF
As q = cv
Hence slope of graph will give capacitance. Slope will be more in parallel combination. Hence capacitance in parallel should be 50µF
capacitance in parallel must be 8µF
Only in option 40µF 10µF
Cparallel = 40 + 10 = 50µF
Cseries = (40 × 10)/(40 + 10) = 8µF