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Question:

Figure shows charge (q) versus voltage (V) graph for series and parallel combination of two given capacitors. The capacitances are:

50µF and 30µF

20µF and 30µF

60µF and 40µF

40µF and 10µF

Solution:

The correct option is D 40µF and 10µF

As q = cv
Hence slope of graph will give capacitance. Slope will be more in parallel combination. Hence capacitance in parallel should be 50µF
capacitance in parallel must be 8µF
Only in option 40µF 10µF
Cparallel = 40 + 10 = 50µF
Cseries = (40 × 10)/(40 + 10) = 8µF