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Question:

Figure shows elliptical path abcd of a planet around the sun S such that the area of triangle csa is 1/4 the area of the ellipse. (See figure) With db as the major axis, and ca as the minor axis. If t1 is the time taken for the planet to go over path abcd and t2 for path cda, then what is the relationship between t1 and t2?

t1=4t2

t1=t2

t1=2t2

t1=3t2

Solution:

Since area of triangle csa is 1/4 of total area of ellipse, therefore:
Area of cda = 1/3 Area of abc
Now that from Kepler's second law areal velocities of the planets are constant which essentially means planets cover equal area in equal time interval.
Hence,
Time taken in covering path abcd and path cda will be in proportion to their respective enclosed areas.
➜t1 = 3t2