Let I0 be the intensity of unpolarised light, incident on the first polaroid. The intensity of light transmitted from the first polaroid will be, I1 = I0cos²θ, or I1 = I0 × 1/2 = I0/2 eq1. Let θ be the angle between the transmission axes of the first and second polaroid (which is placed between two crossed polaroids) and φ be the angle between the second and third polaroid, then θ + φ = 90 (as first and third polaroids are perpendicular to each other), or φ = 90 - θ. Now, the intensity of light transmitted from the second polaroid, I2 = I1cos²θ = (I0/2)cos²θ, and the intensity of light transmitted from the third polaroid, I3 = I2cos²φ = (I0/2)cos²θ × cos²φ, I3 = (I0/2)cos²θ × cos²(90 - θ), or I3 = (I0/2)cos²θsin²θ, or I3 = (I0/2)cos²θsin²θ, or I3 = (I0/2)(sin22θ/4). This is the required expression. Now I3 will be maximum when sin2θ is maximum i.e. sin2θ = 1 = sin90, or 2θ = 90, or θ = 45°