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Question:

Find :∫sin2x−cos2xsinxcosxdx

Solution:

∫Sin2x−Cos2xSinx.Cosx=∫−Cos(2x)0.5⋅Sin(2x)
Let Sin(2x)=t
then dt=Cos(2x)⋅2
then=∫−dtt=−lnt=−ln(Sin(2x))+c