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Question:

Find product of following pairs of monomials: (i) 4, 7p (ii) -8p, 7p (iii) -8p, 7pq (iv) 4p³, -3p (v) 4p, 0

Solution:

(i) 4 × 7 × p = 28p
(ii) -8p × 7p = -56p²
(iii) -8p × 7pq = -56p²q
(iv) 4p³ × -3p = -12p⁴
(v) 4p × 0 = 0