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Question:

Find the amount and the compound interest on Rs 10,000 for 11/2 years at 10%

Solution:

Compounded half yearly:
A=P(1+r/200)^2n × (1+br/100)=10000(1+10/200)^(2) × (1+1/2 × 10/100)
=10000(1.1025)(1.05)=11576.25
Amount=Rs.11,576.25
CI=A−P=Rs.1576.25