Find the Cartesian equation of the line which passes through the point (-2, 4, -5) and is parallel to the line x+3/3 = (4-y)/5 = (z+8)/6.

The ratio of the given line are (3, 5, 6). The required line passes through the point A(-2, 4, -5) and parallel to x+3/3 = (4-y)/5 = (z+8)/6. So, the cartesian equation of the required line are (x-x1)/a = (y-y1)/b = (z-z1)/c. The equation is (x+2)/3 = (y-4)/5 = (z+5)/6