Find the distance of a point 3x - 4y + 12z = 3 from the origin.

The distance from a point P(0,0,0) from the given plane 3x - 4y + 12z = 0 is:
D = |3 × 0 - 4 × 0 + 12 × 0| / √(3)² + (-4)² + (12)² = 3 / √9 + 16 + 144 = 3 / √169 = 3/13 units.