Find the integrating factor of the differential equation (e√x√x - y√x)dxdy = 1

On rearranging the equation, we get:
(e√x√x - y√x)dxdy = 1
⇒dy/dx + y/√x = e√x/√x
which is a first order linear non homogeneous differential equation of the form
dy/dx + P(x).y = Q(x)
thus the integrating factor is:
I.F. = e∫P(x)dx = e∫dx/√x = e2√x