Find the length of the perpendicular drawn from the origin to the plane 2x - 3y + 6z + 21 = 0

Given a plane 2x - 3y + 6z + 21 = 0
We know the formula, the distance of a point P(x1, y1, z1) from the plane Ax + By + Cz + D = 0 is given by
(Ax1 + By1 + Cz1 + D) / √(A² + B² + C²)
We need to calculate the distance from the origin P(0, 0, 0) to the plane.
Distance = (2(0) - 3(0) + 6(0) + 21) / √(2² + (-3)² + 6²) = 21 / √49 = 21/7 = 3
Therefore, the length of the perpendicular drawn from the origin to the plane 2x - 3y + 6z + 21 = 0 is 3.