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Question:

Find the square of the following numbers: (i) 32 (ii) 35 (iii) 86 (iv) 93 (v) 71 (vi) 46

Solution:

(i)32²=(30+2)(30+2)=900+60+60+4=1024
(ii)35²=(30+5)(30+5)=900+150+150+25=1225
(iii)86²=(80+6)(80+6)=6400+480+480+36=7396
(iv)93²=(90+3)(90+3)=8100+270+270+9=8649
(v)71²=(70+1)(70+1)=4900+140+140+1=5041
(vi)46²=(40+6)(40+6)=1600+480+480+36=2116