devarshi-dt-logo

Question:

Find the value of a if[a−b2a+c2a−b3c+d]=[�].Find the value of a if[a−b2a+c2a−b3c+d]=[�].[a−b2a+c2a−b3c+d]=[�][a−b2a+c2a−b3c+d]=[�][a−b2a+c2a−b3c+d]=[�][a−b2a+c2a−b3c+d][[a−b2a+c2a−b3c+da−b2a+c2a−b3c+da−b2a+ca−ba−baa−−bb2a+c2a+c22aa++cc2a−b3c+d2a−b2a−b22aa−−bb3c+d3c+d33cc++dd]]==[�][[��󔼗𕒵𕒵−�]]?

Solution:

Since(a−b2a+c2a−b3c+d)=(�)Equating the matrices we get,a−b=𕒵(1)2a+c=5(2)2a−b=0(3)3c+d=13(4)Now from equation (3) we getb=2aSubstitutingb=2ain equation (1) we get,a𕒶a=𕒵⟹−a=𕒵⟹a=1Hence,a=1.