Find the value of other five trigonometric ratios: cosx = 1/2, x lies in third quadrant.

cosx = 1/2 ∴ secx = 1/cosx = 2
Now ∵ sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x ⇒ sin²x = 1 - (1/2)² = 3/4 ⇒ sinx = ±√3/2
Since x lies in third quadrant, the value of sinx will be negative.
∴ sinx = -√3/2
cscx = 1/sinx = -2/√3
tanx = sinx/cosx = (-√3/2)/(1/2) = -√3
cotx = 1/tanx = -1/√3