Find the value of other five trigonometric ratios: secx=13/5, x lies in fourth quadrant.

secx=13/5⇒cosx=1/secx=5/13
Now ∵sin²x+cos²x=1⟹sin²x=1−cos²x=1−(5/13)²=1−25/169=144/169⟹sinx=±12/13
Since x lies in fourth quadrant, the value of sinx will be negative.
∴sinx=−12/13
cscx=1/sinx=−13/12
tanx=sinx/cosx=(−12/13)(5/13)=−12/5
cotx=1/tanx=−5/12