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Question:

Find the value of sin(11π/3)

Solution:

It is known that the values of sinx repeat after an interval of 2π or 360°.
∴sin(11π/3) = sin(11π/3 + 2 × 2π) = sin(11π/3 + 4π) = sin(23π/3) = sin(8π - π/3) = sin(-π/3) = -sin(π/3) = -√3/2