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Question:

Find the value of: (i) (30 + 4²) × 22 (ii) (2² × 4²) ÷ 2³ (iii) (1²)² + (1³)³ + (1⁴)⁴ (iv) (3² + 4² + 5²)⁰ (v) ((6³)⁶)²

Solution:

(i) (30 + 4²) × 22 = (30 + 16) × 22 = 46 × 22 = 1012
(ii) (2² × 4²) ÷ 2³ = (4 × 16) ÷ 8 = 64 ÷ 8 = 8
(iii) (1²)² + (1³)³ + (1⁴)⁴ = 1² + 1³ + 1⁴ = 1 + 1 + 1 = 3
(iv) (3² + 4² + 5²)⁰ = (9 + 16 + 25)⁰ = 50⁰ = 1
(v) ((6³)⁶)² = (216⁶)² = (216²)⁶ = (46656)²⁶ = 1