Find the values of the letters in the following and give reasons for the steps involved. AB × 3 = CAB

In the given problem, if B × 3 has to end with B, then B has to be either 0 or 5, because only 0 or 5, when multiplied by 3, will give the same number. If B = 5, then there will be a carry-over, which will not give the next product as CA. Thus, B = 0. Also, A × 3 ends with A, so A = 5. And 3 × 5 = 15 ∴ C = 1 Hence, A = 5, B = 0 and C = 1.