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Question:

Find:(i)9^(3/2) (ii)32^(2/5) (iii)16^(3/4) (iv)125^(1/3)

Solution:

(i) (9)^(3/2)
Express 9 in terms of 3 = (3^2)^(3/2) = 3^(23/2) = 3^3 = 27
(ii) 32^(2/5)
Express 32 in terms of 2 = (2^5)^(2/5) = 2^(5
2/5) = 2^2 = 4
(iii) 16^(3/4)
Express 16 in terms of 4 = (4^2)^(3/4) = 4^(23/4) = 4^(3/2) = (4^(1/2))^3 = 2^3 = 8
(iv) 125^(1/3)
Express 125 in terms of 5 = (5^3)^(1/3) = 5^(3
1/3) = 5^1 = 5