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Question:

For a cell involving one electron, Ecell0 = 0.59V at 298K, the equilibrium constant for the cell reaction is : [Given that 2.303RT/F = 0.059V at T = 298K]

1.0×102

1.0×105

1.0×1010

1.0×1030

Solution:

Correct option is C. 1.0×1010
Ecell = Ecell0 - 0.059/n logQ. ((At equilibrium, Q = Keq AND Ecell = 0)
0 = Ecell0 - 0.059/1 logKeq (from equation (i))
logKeq = Ecell0/0.059 = 0.59/0.059 = 10
Keq = 10^10 = 1×1010