Question:

For a first order reaction A→P, the temperature (T) dependent rate constant (k) was found to follow the equation logk = −(2000)/T + 6.0. The pre-exponential factor A and the activation energy Ea, respectively, are:

1.0×10⁶s⁻¹ and 16.6 kJmol⁻¹

1.0×10⁶s⁻¹ and 38.3 kJmol⁻¹

6.0s⁻¹ and 16.6 kJmol⁻¹

1.0×10⁶s⁻¹ and 9.2 kJmol⁻¹

Given, logK = 6 - 2000/T
Since, logK = logA - Ea/(2.303RT) ⇒ logA = 6 and -Ea/(2.303R) = -2000
So, A = 10⁶ sec⁻¹ and Ea = 38.3 kJ/mole