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Question:

For a given exothermic reaction, KP and K'P are the equilibrium constants at temperatures T1 and T2 respectively. Assuming that the heat of reaction is constant in the temperature range between T1 and T2, it is readily observed that:

KP < K'P

KP = KP

KP = 1/K'P

KP > K'P

Solution:

For a given exothermic reaction, KP and K'P are the equilibrium constants at temperatures T1 and T2 respectively. Assuming that the heat of reaction is constant in the temperature range between T1 and T2, it is readily observed that KP > K'P.

log(K2/K1) = ΔHo/(2.303R)(1/T1 - 1/T2)