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Question:

For nth order reaction (dx/dt) = Rate = k[A0]^n. Graph between log(rate) against log[A0] is of the type. Lines P, Q, R, S are for the order:

P4,Q7,R6,S5

P4,Q5,R6,S7

P5,Q6,R7,S4

P7,Q6,R5,S52

Solution:

Given that, Rate = k[A0]^n — 1
Taking log on both sides, we get
log rate = n log[A]o + log k
As n increases the slope of graph increases.
Hence, P7,Q6,R5,S52