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Question:

For periodic motion of small amplitude A, the time period T of this particle is proportional to

A√mα

1/A√mα

A√αm

A√2αm

Solution:

The dimensions of α are V(x)x⁴=Energy/Length⁴=ML²T⁻²/L⁴=[ML⁻²T⁻²]
It is clear that 1/A√mα has dimensions of time.