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Question:

For photoelectric emission from certain metal the cut-off frequency is v. If radiation of frequency 2v impinges on the metal plate, the maximum possible velocity of the emitted electron will be: (m is the electron mass)

√2hvm

2√hvm

√hv(2m)

√hvm

Solution:

K.E=E−ϕ
12mv2max=h2v−hv
vmax=√2hvm