Eduprobe
Question:
For photoelectric emission from certain metal the cut-off frequency is v. If radiation of frequency 2v impinges on the metal plate, the maximum possible velocity of the emitted electron will be: (m is the electron mass)
√2hvm
2√hvm
√hv(2m)
√hvm
Solution:
K.E=E−ϕ
12mv2max=h2v−hv
vmax=√2hvm