62 kJ
21 kJ
16 kJ
13 kJ
Correct option is D. 62 kJSolution:- (D) 62 kJΔH = n∫(T₁)^(T₂) C_p.m dT = 3 × ∫(300)^(1000) (23+0.01T)dT = 3[23(1000-300)+0.01/2(1000²-300²)] = 61950J ≈ 62kJ