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Question:

For the cell reaction 2Fe³⁺(aq) + 2I⁻(aq) → 2Fe²⁺(aq) + I₂(aq), E°cell = 0.24V at 298K. The standard Gibbs energy (ΔrG°) of the cell reaction is: Given that Faraday constant F = 96500 C mol⁻¹

46.32kJmol⁻¹

23.16kJmol⁻¹

-46.32kJmol⁻¹

-23.16kJmol⁻¹

Solution:

Correct option is C.
ΔG° = -nFE°cell = 2 × 96500 × 0.24 Jmol⁻¹ = -46320 Jmol⁻¹ = -46.32 kJmol⁻¹