-13d[H_2]dt=-12[NH_3dt
-d[N_2]dt=12d[NH_3]dt
-d[N_2]dt=2d[NH_3]dt
3d[H_2]dt=2d[NH_3]dt
Correct option is C. -d[N_2]/dt = 2d[NH_3]/dtN_2 + 3H_2 ⇌ 2NH_3rate of reaction is given as -d[N_2]/dt = -1/3d[H_2]/dt = +1/2d[NH_3]/dt