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Question:

For the electrochemical cell M|M+||X−|X, Eo(M+|M) = 0.44 V and Eo(X|X−) = 0.33 V. From this data one can deduce that: If 0.5 amp current is passed through acidified silver nitrate. Ecell = 0.77 V

M+X → M++X− is the spontaneous reaction

M++X− → M+X is the spontaneous reaction

Ecell = 0.77 V

Ecell = −0.77 V

Solution:

M++X− → M+X is spontaneous because for the cell represented by M|M+||X−|X, the value of Eo is positive i.e., (0.44 − 0.33) V = 0.11 V