2.303RT+1.1F
−2F
2.303RT−2F
1.1F
Zn + Cu²⁺ → Zn²⁺ + Cu
E⁰cell = 1.1V (given)
Ecell = E⁰cell − (2.303RT/nF)log[Zn²⁺]/[Cu²⁺]
Given that [Zn²⁺] = 10[Cu²⁺]
Ecell = 1.1 − (2.303RT/2F)log10
Ecell = 1.1 − (2.303RT/2F)
ΔG = −nFEcell
ΔG = −2F[1.1 − (2.303RT/2F)]
ΔG = −2.2F + 2.303RT