For the following reaction, the mass of water produced from 445g of C57H110O6 is: 2C57H110O6(s) + 163O2(g) → 114CO2(g) + 110H2O(l)<p></p>

The correct option is A 495g
Moles of C57H110O6(s) = 445/890 = 0.5 moles
2C57H110O6(s) + 163O2(g) → 114CO2(g) + 110H2O(l)
From balanced equation we have,
nH2O = 110/2 = 55
mH2O = 55 × 18 = 495g

Eduprobe

Question:

For the following reaction, the mass of water produced from 445g of C57H110O6 is: 2C57H110O6(s) + 163O2(g) → 114CO2(g) + 110H2O(l)

Solution: