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Question:

For the following reactions, equilibrium constants are given: S(s) + O_2(g) ⇌ SO_2(g); K_1 = 10^52 2S(s) + 3O_2(g) ⇌ 2SO_3(g); K_2 = 10^129 The equilibrium constant for the reaction, 2SO_2(g) + O_2(g) ⇌ 2SO_3(g) is:

10^181

10^154

10^25

10^77

Solution:

Correct option is C. 10^25
Solution:- (C) 10^25
S(s) + O_2(g) ⇌ SO_2(g); K_1 = 10^52 ——- (1)
2S(s) + 3O_2(g) ⇌ 2SO_3(g); K_2 = 10^129 —– (2)
2SO_2 + O_2(g) ⇌ 2SO_3(g); K_3 = x
Multiplying equation (1) by 2;
2SO(s) + 2O_2(g) ⇌ 2SO_2(g) ; K'_1 = 10^104 —– (3)
⇒ Substracting (3) from (2); we get
2SO_2(g) + O_2(g) ⇌ 2SO_3(g); K_eq = K_2K_1'=10^(129 - 104) = 10^25