150
72
166
59
Correct option is B. 166H₂(g) + I₂(g) → 2HI(g)Apply Arrhenius equationlog₁₀(K₂/K₁) = Ea/2.303R(1/T₁ - 1/T₂)log₁₀(1/2.5 × 10⁻⁴) = Ea/2.303 × 8.314(1/600 - 1/800)∴ Ea ≈ 166 kJ/mol