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Question:

For the reaction 2AgCl(s) + H₂(g)(1atm) → 2Ag(s) + 2H⁺(0.1M) + 2Cl⁻(0.1M), ΔG⁰ = -43600 J at 25°C. Calculate the e.m.f of the cell. [log₁₀⁻ⁿ = -n]

Solution:

ΔG⁰ = -nFE⁰cell
-43600 = -2 × 96500 × E⁰cell
E⁰cell = 0.23V
Ecell = E⁰cell - (0.0591/n)log₁₀[H⁺]²[Cl⁻]²PH₂
Ecell = 0.23V - (0.0591/2)log₁₀[0.1]²[0.1]²1
Ecell = 0.348V