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Question:

For the reaction, 3A + 2B → C + D, the differential rate law can be written as:

3d[A]/dt=d[C]/dt=k[A]n[B]m

-d[A]/dt=d[C]/dt=k[A]n[B]m

⅓d[A]/dt=d[C]/dt=k[A]n[B]m

+1/3d[A]/dt=d[C]/dt=k[A]n[B]m

Solution:

For the reaction, 3A + 2B → C + D, the differential rate law can be written as ⅓d[A]/dt=d[C]/dt=k[A]n[B]m as: Rate, r = ⅓d[A]/dt = ½d[B]/dt = d[C]/dt = d[D]/dt = k[A]n[B]m.