N2(g)+3H2(g)→2NH3(g)
2NO2(g)→N2O4(g)
2SO2(g)+O2(g)→2SO3(g)
2HI(g)→H2(g)+I2(g)
For the reaction, 2HI(g)→H2(g)+I2(g), ΔH is equal to ΔU. The relationship between ΔH and ΔU is given by:
ΔH = ΔU + ΔnRT
where:
For the reaction 2HI(g) → H2(g) + I2(g), the change in the number of moles of gas (Δn) is:
Δn = (moles of gaseous products) - (moles of gaseous reactants) = (1 + 1) - 2 = 0
Since Δn = 0, the equation becomes:
ΔH = ΔU + 0
Therefore, ΔH = ΔU for this reaction.