For x² ≠ nπ + 1, n ∈ ℕ (the set of natural numbers), the integral ∫x√(2sin(x²)-sin²(x²))/(2sin(x²)+sin²(x²))dx is equal to (where c is a constant of integration).
loge√√√(1/2sec²(x²))+c
1/2loge√√√(sec²(x²/2))+c
1/2loge√√sec(x²)+c
loge√√√sec(x²/2)+c
Solution:
Put (x²)=t ⇒ 2xdx = dt ∴I = 1/2 ∫√(1-cost)/(1+cost)dt = 1/2 ∫tan(t/2)dt = ln|sec(t/2)| + c I = ln|sec(x²/2)| + c.