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Question:

Formation of polyethylene from calcium carbide takes place as follows: CaC2 + 2H2O → Ca(OH)2 + C2H2; C2H2 + H2 → C2H4; nC2H4 → (CH2-CH2)n. The amount of polyethylene obtained from 64.0 kg of CaC2 is:

27 kg

24 kg

28 kg

22 kg

Solution:

M CaC2 = 40 + 2 × 12 = 64 g/mol,
No. of moles of CaC2 in 64 Kg = 1000 mole
= No. of moles of C2H2 formed
= No. of moles of C2H4 formed
Thus n = 1000
Amount of polyethylene = 28 × 1000 = 28000 g = 28 kg