Formation of polyethylene from calcium carbide takes place as follows: CaC₂ + 2H₂O → Ca(OH)₂ + C₂H₂ C₂H₂ +H₂ → C₂H₄ nC₂H₄ → +CH₂ - CH₂ +ₙ The amount of polyethylene obtained from 64.0 kg of CaC₂ is:

Correct option is D. 28 kg
Mass of CaC₂ = 64 Kg
Moles of CaC₂ = 64/64 = 1000 mol
CaC₂ + 2H₂O → Ca(OH)₂ + C₂H₂
For 1000 mole of CaC₂, We get 1000 mole of C₂H₂
C₂H₂ + H₂ → C₂H₄
For 100 mole of C₂H₂, we get 1000 mole of C₂H₄
nC₂H₄ → (CH₂-CH₂)ₙ
For n mole C₂H₂, we get 1 mole of polyethene.
For 1000 mole of C₂H₂, we get (1000/n) × 1
Number of moles of polyethylene formed are 1000/n.
Molecular weight of polyethylene is n × [(2 × 12) + (2 × 4)] = 28n
Mass of polyethylene produced = Number of moles × Molecular weight = (1000/n) × 28n = 28000 gram = 28 kg
Option D is correct.