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Question:

Four bulbs B1, B2, B3 and B4 of 100 W each are connected to 220 V main as shown in the figure. The reading in an ideal ammeter will be :

0.90 A

0.45 A

1.35 A

1.80 A

Solution:

Answer is C
Current through each bulb=100/220=5/11A
The ammeter reads only the Current which passing through B2, B3, B4
Therefore current through ideal ammeter =3 × 5/11=1.35A.