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Question:

From a point on the ground, the angles of elevation of the bottom and the top of a transmission tower fixed at the top of a 20m high building are 45° and 60° respectively. Find the height of the tower.

Solution:

In ΔBCD,
BC/CD = tan 45°
CD = 20m
In ΔACD,
AC/CD = tan 60°
AB + BC/CD = √3
AB = (20√3 - 20)m