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Question:

From a solid sphere of mass M and radius R, a spherical portion of radius R/2 is removed, as shown in the figure. Taking gravitational potential V = 0 at r = ∞, the potential at the centre of the cavity thus formed is :(G = gravitational constant)

-GM/2R

+GM/R

-GM/R

+GM/3R

Solution:

Gravitational potential at any inside point is given as V = -GM/2R³(3R² - r²)(i) for r = R/2 V = +GM/8R
Subtracting potential due to cavity of mass Mc = M/8 and Rc = R/2
Gravitational potential at center is obtained by substituting r = 0 in equation (i) = +GM/8R
V = +GM/8R - (-GMc/2Rc) = +GM/8R + 3GM/8(2R/2) => V = -GM/R